Question

The charge on a particle is 100 times that of electron. It is revolving in a circular path of radius 0.8 m at a frequency of ${10}^{11}$ revolutions per second. The magnetic field at the centre of path will be-

• A. ${10}^{-7}{\mu }_0$
• B. $\frac{{10}^{-7}}{{\mu }_0}$
• C. ${10}^{-17}{\mu }_0$
• D. ${10}^{-6}{\mu }_0$

Answer 1

The correct option is C ${10}^{-17}{\mu }_0$

Given: q=100e ,r=0.8

Solution : Q=ne

$i=\frac{q}{t}=\frac{ne}{t}=\frac{100\times 1.6\times {10}^{-19}}{1}=1.6\times {10}^{-17}$

Formula of magnetic field at the centre of path is :

$B=\frac{{\mu }_{0}i}{2r}$

$B=\frac{{\mu }_0\times 1.6\times {10}^{-17}}{2\times 0.8}={\mu }_{0\times {10}^{-17}}$

Hence the correct option is C