The cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to the distances less than 500 m. If a cheetah spots his prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h?

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Solution

Step 1:Given data:
Average velocity of cheetah = 90 km/h
Distance of prey = 100 m
Average velocity of cheetah = 90 km/h = $90 \times \frac{5}{18} =$ 25 m/s.
Step 2:Finding the time:
$T i m e = \frac{D i s \tan c e}{s p e e d} = \frac{100}{25} = 4 s e c o n d s .$
Hence, the cheetah will catch his prey in 4 seconds.

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The cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to the distances less than 500 m. If a cheetah spots his prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h?

Step 1:Given data:Average velocity of cheetah = 90 km/hDistance of prey = 100 mAverage velocity of cheetah = 90 km/h = 90×518=25 m/s.Step 2:Finding the time:Time=Distancespeed=10025=4seconds.Hence, the cheetah will catch his prey in 4 seconds.