The chord of contact
of tangents from a point P to a circle passes through Q. If $l_{1}$ and $l_{2}$ are the length of the tangents from P and Q to the circle then PQ is
equal to

\frac{l_{1} + l_{2}}{2}

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\frac{l_{1} - l_{2}}{2}

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\sqrt{l_{1}^{2} + l_{2}^{2}}

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2 \sqrt{l_{1}^{2} + l_{2}^{2}}

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Solution

The correct option is C $\sqrt{l_{1}^{2} + l_{2}^{2}}$
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Similar questions

Q. The chord of contact of tangents from a point 'P' to a circle passes through Q. If

l_{1} a n d l_{2}

are the lengths of the tangents from P and Q to the circle, then PQ is equal to

Q. The chord of contacts of tangents from a point P to a circle passes through Q,if

l_{1}

and

l_{2}

are the tangents passing from P and Q to the circle ,then PQ is equal to

Q. Assertion :The chord of contact of tangent from a point

P

to a circle passes through

Q

. If

l_{1}

and

l_{2}

are the lengths of the tangents from

P

and

Q

to the circle, then

P Q

is equal to

\sqrt{{l_{1}}^{2} + {l_{2}}^{2}}

Reason: The equation of chord of contact of tangents from the point

P (x_{1}, y_{1})

to the circle

x^{2} + y^{2} = a^{2}

x x_{1} + y y_{1} = a^{2}

A monoatomic ideal gas, initially at temperature $T_{1}$ is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature. $T_{2}$ by releasing the piston suddenly. If $L_{1}$ and $L_{2}$ are the lengths of the gas column before and after expansion respectively, then $\frac{T_{1}}{T_{2}}$ is given by