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Question

The chords AC and ZX are of same length. P is the center of the circle of radius 10 units. If ZY = 6 units, the length of PB is units.


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Solution

The distance of the chord ZX is represented by the perpendicular from the chord to the center, i.e., PY.

Hence, PZY forms a right triangle of hypotenuse PZ as radius of the circle.
PZ2=ZY2+PY2
PY=PZ2ZY2=102+62
PY==64=8 units

The chords AC and ZX are of same length.
Hence, they are equidistance from the center.
PY=PB=8 units

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