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Byju's Answer
Standard XII
Physics
Acceleration in 2D
The circle ...
Question
The circle
x
2
+
y
2
−
8
x
+
4
y
+
4
=
0
touches:
A
x-axis
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B
y-axis
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C
Both axis
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D
Neither x-axis nor y-axis
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Solution
The correct option is
D
y-axis
x
2
+
y
2
−
8
x
+
4
y
+
4
=
0
⇒
(
x
2
−
8
x
+
16
)
+
(
y
2
+
4
y
+
4
)
=
16
⇒
(
x
−
4
)
2
+
(
y
+
2
)
2
=
4
2
Center is
(
4
,
−
2
)
and radius is
4
Hence given circle touches y-axis
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2
+
y
2
−
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x
−
4
y
+
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=
0
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)
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