The circle $x^{2} + y^{2} - 3 x - 4 y + 2 = 0$ cuts $x - a x i s$ at

(2, 0), (- 3, 0)

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(3, 0), (4, 0)

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(1, 0), (- 1, 0)

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(1, 0), (2, 0)

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Solution

The correct option is D $(1, 0), (2, 0)$
$x^{2} + y^{2} - 3 x - 4 y + 2 = 0$
At $x$ intercept value of $y = 0$

Then equation becomes,
$\Rightarrow$ $x^{2} - 3 x + 2 = 0$
$\Rightarrow$ $x^{2} - 2 x - x + 2 = 0$
$\Rightarrow$ $x (x - 2) - 1 (x - 2) = 0$
$\Rightarrow$ $(x - 2) (x - 1) = 0$
$∴$ $x = 2$ and $x = 1$

$∴$ The circle $x^{2} + y^{2} - 3 x - 4 y + 2 = 0$ cut x-axis at $(1, 0), (2, 0)$

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The circle x2+y2−3x−4y+2=0 cuts x−axis at

The correct option is D (1,0),(2,0)x2+y2−3x−4y+2=0At x intercept value of y=0Then equation becomes,⇒ x2−3x+2=0⇒ x2−2x−x+2=0⇒ x(x−2)−1(x−2)=0⇒ (x−2)(x−1)=0∴ x=2 and x=1∴ The circle x2+y2−3x−4y+2=0 cut x-axis at (1,0),(2,0)

The circle $x^{2} + y^{2} - 3 x - 4 y + 2 = 0$ cuts $x - a x i s$ at