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Question

# The circuit shown below works as differential amplifier. Both transistor are of silicon material and have β = 100, then the value of V0 if Vi = 5 V will be _____V. (Take VBE=0.7 Volts)

A
0 V
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B
12 V
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C
8 V
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D
6 V
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Solution

## The correct option is B 12 V Let us consider Q2 to be off and Q1 is in the active mode, based on the voltage given , then IE1=1mA IC1=1mA = β1+βIE1 =100101× 1 = 0.99 mA and VCBI=12−5×0.99−5 = 2.05 V Since VCBI is +ve , Q1 is in active mode. Assume VBEI = 07 V, VE=VB−VBE1 = 5 - 0.7 V = 4.3 V ∵ VE=4.3 means that VBE2=VB2−VE = 2.5 - 4.3 = - 1.8 V Since, VBE2 is negative , our assumptions of Q2 being off is confirmed . As no current flows through Q2 So , V0 = 12 V

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