wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The circuit shown in Figure contains three resistors R1=100Ω, R2=50Ω, and R3=20Ω and cells of emfs E1=2V and E2. The ammeter indicates a current of 50 mA. Determine the currents in the resistors and the emf of the second cell. The internal resistance of the ammeter and of the cells should be neglected.
155579.jpg

Open in App
Solution

Given : E1=2 V R1=100Ω R2=50Ω R3=20Ω
Kirchhoff'l loop law in ABCDA : E1+(I+0.05)R1+IR2=0
2+(I+0.05)(100)+I(50)=0 I=0.02 A

Kirchhoff'l loop law in BGEFB : E2+(0.05)R3+(I+0.05)R1=0
E2+(0.05)(20)+(0.02+0.05)(100)=0 E2=4 V
Hence current flowing through R1, I1=0.050.02=0.03 A =30 mA towards right

582061_155579_ans.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrical Instruments
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon