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Question

The circuit shown in Figure is in steady state. Find the charges on the capacitors C1 and C2 respectively :

156497_93adfd7fa70c41b999c14fbebbda150c.png

A
3μC,12μC
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B
4μC,9μC
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C
2μC,12μC
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D
3μC,0
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Solution

The correct option is A 3μC,12μC
In steady state, current will flow as shown in Figure,
I=6/(10+10)=0.30A
Potential difference across C1 is same as that across 10Ω on left side. So
V1=10I=3V
Charge on C1 is q1=C1V1=1×3=3μC
We can see that potential difference across C2 is 6 V. So charge on C2 is q2=C2V2=2×6=12μC.
327716_156497_ans_d835274ba9fe4bd69daeed056b156b0c.png

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