The circumcentre of the triangle formed by the lines, xy+2x+2y+4=0 and x+y+2=0 is
1. 1) As the given equation of lines,
xy+2x+2y+4=0,----------(1)
x+y+2=0-----------(2)
on solving eq (1),we get
x×(x+2)+2×(y+2)=0
(x+2)×(y+2)=0-------(3)
so here equation of three line ar obtained which is as follows,
X+Y+2=0,
X+2=0 ,and
Y+2=0
these lines form a triangle as shown in figure .
Concept of circumcentre:-The circumcentre of a triangle is the point of intersection of the perpendicular bisectors of the side of triangle.
Acc to given equations , triangle ABC will form as shown in the figure
These equations will form a right angle triangle so, circumcentre will be at mid point of BC so, circumcentre is (-2,-2)