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Question

# The circumference of the first Bohr orbit in H atom is 3.322 × 10−10 m. What is the velocity of the electron of this orbit?

A

2.19 × 106 m/s

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B

4.19 × 106 m/s

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C

3.57 × 106 m/s

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D

6.00 × 106 m/s

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Solution

## The correct option is A 2.19 × 106 m/s From Bohr's postulates, we know that → An electron can move only in those orbits for which its angular momentum is an integral multiple of h2π. ⇒ mevr = nh2π Now, According to Bohr's model, mvr = nh2π; Given that n = 1 & 2πr (circumference) = 3.322 × 10−10 m v = nh2πmr = 1 × (6.626 × 10−34 Js)(9.1 × 10−31 kg) × 3.322 × 10−10 m = 2.19 × 106m s−1

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