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Question

The circumference of the first Bohr orbit in H atom is 3.322 × 1010 m. What is the velocity of the electron of this orbit?



Correct Answer
A

2.19 × 106 m/s

Your Answer
B

4.19 × 106 m/s

Your Answer
C

3.57 × 106 m/s

Your Answer
D

6.00 × 106 m/s


Solution

The correct option is A

2.19 × 106 m/s


From Bohr's postulates, we know that

An electron can move only in those orbits for which its angular momentum is an integral multiple of h2π.

mevr = nh2π

Now,

According to Bohr's model,

mvr = nh2π;

Given that n = 1 & 2πr (circumference)

= 3.322 × 1010 m

v = nh2πmr = 1 × (6.626 × 1034 Js)(9.1 × 1031 kg) × 3.322 × 1010 m

= 2.19 × 106m s1

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