Question

The closed container shown in the figure is filled with water and accelerating. Then, minimum and maximum pressure is at -

• A. $A$ and $B$ respectively
• B. $B$ and $C$ respectively
• C. $B$ and $D$ respectively
• D. $D$ and $A$ respectively

Answer 1

The correct option is B $B$ and $C$ respectively

For the given accelerated container, the pressure difference in liquid along horizontal direction is given by,
$\Delta P=\rho ax$
The pressure will increase in a direction opposite to that of acceleration of container.
i.e $P_A>P_B....\left(1\right)$
and $P_C>P_D...\left(2\right)$

The pressure difference for liquid due to vertical depth is given as:
$\Delta P=\rho gh$
[$\because$ The pressure will increase in vertically downward direction]
i.e $P_C>P_A...\left(3\right)$
and $P_D>P_B...\left(4\right)$


On comparing Eq.$\left(1\right),\left(2\right),\left(3\right),\left(4\right)$:
$P_B$ is minimum and $P_C$ is maximum