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Coagulation

The coagulati...

Question

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of $A s_{2} S_{3}$ are given below:
$I . (N a C l) = 52, I I . (B a C l_{2}) = 0.69, I I I . (M g S O_{4}) = 0.22$
The correct order of their coagulating power is

I > II > III

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II > I > III

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III > II > I

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III > I > II

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Solution

The correct option is C III > II > I
$C o a g u l a t i n g p o w e r \propto \frac{1}{C o a g u l a t i o n v a l u e}$
Lower the coagulation value, higher is the coagulating power so, the correct order is :
$M g S O_{4} (I I I) > B a C l_{2} (I I) > N a C l (I)$

Suggest Corrections

Similar questions

A s_{2} S_{3}

I . (N a C l) = 52, I I . (B a C l_{2}) = 0.69, I I I . (M g S O_{4}) = 0.22

A s_{2} S_{3}

N a C l, i t i s 52,

B a C l_{2}, i t i s 0.69,

M g S O_{4}, i t i s 0.22

{A g}_{2} S_{3}

I

N a C l = 52

I I

K C l = 51

I I I

B a {C l}_{2} = 0.69

I V

M g {S O}_{4} = 0.22

A s_{2} S_{3}

N a C l, i t i s 52,

B a C l_{2}, i t i s 0.69,

M g S O_{4}, i t i s 0.22

A s_{2} S_{3}

N a C l (52)

B a C l_{2} (0.69)

M g S O_{4} (0.22)

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