Question

The coefficient of friction between a body and the surface of an inclined plane at ${45}^o$ is 0.5. If g=9.8 $m/s^2$ the acceleration of the body downwards in $m/s^2$ is

• A.
• B.
• C.
• D. 4.9

Answer 1

The correct option is A

$a=g(sin\theta -\mu cos\theta )=9.8(sin{45}^o-0.5cos{45}^o)$
$\frac{4.9}{\sqrt{2}}m/se{c}^2$