Question

The coefficient of mean deviation from median of observations $40,62,54,90,68,76$ is

Answer 1

Deviation about median:

Arranging the given data in ascending order.

$40,54,62,68,76,90$

$n=6$ (even)

$Median=\frac{valueof{3}^{rd}observation+valueof{4}^{th}observation}{2}$

Median M $=\frac{62+68}{2}=65$

Mean deviation about median M.D$=\frac{\left|40-65\right|+\left|54-65\right|+\left|62-65\right|+\left|68-65\right|+\left|76-65\right|+\left|90-65\right|}{65}$

$$\begin{gathered} =\frac{25+11+3+3+11+25}{65} \\ =1.2 \end{gathered}$$

Therefore,Mean deviation about median $=1.2$