The coefficient of mutual inductance of two coils is $5 H .$ The current through the primary coil is reduced to zero value from $3 A$ in $1$ millisecond. The induced e.m.f. in the secondary coil will be :

30 k V

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1.67 k V

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15 k V

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600 V

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Solution

The correct option is C $15 k V$

$ϕ = L i$
$E m f = \frac{d ϕ}{d t} = L \frac{d i}{d t}$
$= 5 \times \frac{3}{10^{- 3}}$
$= 15 \times 10^{3} V$
= $15$ kV

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The coefficient of mutual inductance of two coils is 5H. The current through the primary coil is reduced to zero value from 3A in 1 millisecond. The induced e.m.f. in the secondary coil will be :

The correct option is C 15kV ϕ=LiEmf=dϕdt=Ldidt =5×310−3 =15×103V =15 kV

The coefficient of mutual inductance of two coils is $5 H .$ The current through the primary coil is reduced to zero value from $3 A$ in $1$ millisecond. The induced e.m.f. in the secondary coil will be :

The correct option is C $15 k V$

$ϕ = L i$
$E m f = \frac{d ϕ}{d t} = L \frac{d i}{d t}$
$= 5 \times \frac{3}{10^{- 3}}$
$= 15 \times 10^{3} V$
= $15$ kV