You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Friction General Understanding

The coefficie...

Question

The coefficient of static friction $μ_{o}$ between block A of mass 2 kg and the table as shown in the figure is 0.2 What would be the maximum mass value of block B so that the blocks do not move? The string and the pulley are asumed to be smooth and massless.
$(g = 10 m / s^{2})$

2.0 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.0 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2 kg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.4 kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.2 kg
$\begin{matrix} A p p l y c o n d i t i o n o f n o s l i p p i n g T < 0.1 \times N T_{max} = 0.1 \times 20 = 2 T_{max} = M_{max} \times g 2 = M \times 10 M = 0.2 \end{matrix}$
Hence, Option $C$ is correct.

Suggest Corrections

Similar questions

Q. The coefficient of static friction is

0.2

between block

A

of mass

2 kg

and the table as shown in the figure. What would be the maximum mass value of block

B

so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless

(g = 10 {m/s}^{2})

Q. The coefficient of static friction,

μ_{s}

, between block

A

of mass 2 kg and the table as shown in the figure is

0.2.

What would be the maximum mass value of block

B

so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.

(g = 10 {m/s}^{2})

Q. The coefficient of static friction is

0.2

between block

A

of mass

2 kg

and the table as shown in the figure. What would be the maximum mass value of block

B

so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless

(g = 10 {m/s}^{2})

Q. The coefficient of static friction,

μ_{s}

, between block

A

of mass 2 kg and the table as shown in the figure is

0.2.

What would be the maximum mass value of block

B

so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.

(g = 10 {m/s}^{2})

The coefficient of static friction between the block of 2 kg and the table shown in figure is $μ$ s = 0.2. what should be the maximum value of m so that the blocks do not move? Take g = 10 $m / s^{2}$ . The string and the pulley are light and smooth.

Join BYJU'S Learning Program

The coefficient of static friction μo between block A of mass 2 kg and the table as shown in the figure is 0.2 What would be the maximum mass value of block B so that the blocks do not move? The string and the pulley are asumed to be smooth and massless. (g=10m/s2)

The correct option is C 0.2 kgApplyconditionofnoslippingT<0.1×NTmax=0.1×20=2Tmax=Mmax×g2=M×10M=0.2Hence, Option C is correct.

The coefficient of static friction $μ_{o}$ between block A of mass 2 kg and the table as shown in the figure is 0.2 What would be the maximum mass value of block B so that the blocks do not move? The string and the pulley are asumed to be smooth and massless.
$(g = 10 m / s^{2})$

The correct option is C 0.2 kg
$\begin{matrix} A p p l y c o n d i t i o n o f n o s l i p p i n g T < 0.1 \times N T_{max} = 0.1 \times 20 = 2 T_{max} = M_{max} \times g 2 = M \times 10 M = 0.2 \end{matrix}$
Hence, Option $C$ is correct.