The correct option is C 13
We have,
(1−x)(2−x2)(3−x3)⋯(20−x20)
=(x−1)(x2−2)(x3−3)⋯(x20−20)
Highest possible coefficient of x in above expansion is x210.
Consider integer partitions with distinct part of 210−203=7.
The ways of writing 7 as a sum of distinct positive integers are 7,6+1,5+2,4+3,4+2+1
So, in order to obtain x203 coefficient, x7 coefficient from the product of terms has to be excluded.
∴ Required coefficient is given by −7+1⋅6+2⋅5+3⋅4−1⋅2⋅4=13