wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+(1+x)23++(1+x)30

A
31C621C6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
31C6+21C6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.31C6+3.21C6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
31C6+1021C6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 31C621C6
(1+x)21+(1+x)22+(1+x)23++(1+x)30=(1+x)21{(1+x)101}(1+x)1=1x[(1+x)31(1+x)21]
coefficient of x5 = coefficient of x6 in [(1+x)31(1+x)21]
coefficient of x5 =31C621C6

flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Term
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon