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Question

(1+x)21+(1+x)22+...+(1+x)30 coefficient of x5

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Solution

(1+x)21+(1+x)22++(1+x)30=(1+x)21(1+x)101x
co efficient of x5 in 1x((1+x)31(1+x)21) will be equal to coefficient of x6 in (1+x)31(1+x)21
So the coefficient is 31C621C6

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