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Question

The coefficient of x5 in the expression of (1+x)21+(1+x)22+....+(1+x)30 is:

A
51C5
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B
9C5
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C
31C621C6
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D
30C5+20C5
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Solution

The correct option is C 31C621C6
T.E coefficient of x5 in (1+x)21+.......+(1+x)30
=(1+x)21[1+(1+x)+(1+x)2+......+(1+x)9]
=(1+x)21[(1+x)101(1+x)1]
=(1+x)21[(1+x)101x]
=1x[(1+x)31(1+x)21]
coeff. is 31C621C6

1182428_1293179_ans_fc0a968e18334920a41bdb55083ef9bd.jpg

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