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Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+(1+x)23++(1+x)30

A
31C621C6
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B
31C6+21C6
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C
2.31C6+3.21C6
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D
31C6+1021C6
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Solution

The correct option is A 31C621C6
(1+x)21+(1+x)22+(1+x)23++(1+x)30=(1+x)21{(1+x)101}(1+x)1=1x[(1+x)31(1+x)21]
coefficient of x5 = coefficient of x6 in [(1+x)31(1+x)21]
coefficient of x5 =31C621C6

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