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Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+.....+(1+x)30 is

A
51C5
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B
9C5
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C
31C621C6
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D
30C5+20C5
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Solution

The correct option is B 31C621C6
We have,
(1+x)21+(1+x)22+.....+(1+x)30

This is in a G.P with a=(1+x)21,r=(1+x)

=(1+x)21{(1+x)101(1+x)1}

=1x{(1+x)31(1+x)21}

Therefore, coefficient of x5 in the given expansion

= Coefficient of x5 in [1x{(1+x)31(1+x)21}]

= Coefficient of x6 in {(1+x)31(1+x)21}

=31C621C6.

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