CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+.....+(1+x)30 is

A
51C5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9C5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
31C621C6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
30C5+20C5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 31C621C6
We have,
(1+x)21+(1+x)22+.....+(1+x)30

This is in a G.P with a=(1+x)21,r=(1+x)

=(1+x)21{(1+x)101(1+x)1}

=1x{(1+x)31(1+x)21}

Therefore, coefficient of x5 in the given expansion

= Coefficient of x5 in [1x{(1+x)31(1+x)21}]

= Coefficient of x6 in {(1+x)31(1+x)21}

=31C621C6.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon