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Question

The coefficient of x7 in the expansion of (1−x4)(1+x)9 is

A
48
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B
-24
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C
64
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D
-48
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Solution

The correct option is B -48
(1x4)(1+x)9
By using expansion of (1+x)n we get,
(1x4)[9C0+9C1x+9C2x2+9C3x3+9C4x4+9C5x5+9C6x6+9C7x7+9C8x8+9C9x9]
Now coefficient of x7 in this expansion will be
1×(9C7)1(9C3)
9!7!2!9!3!6!
3684
48

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