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Byju's Answer
Standard XII
Mathematics
Multinomial Expansion
The coefficie...
Question
The coefficient of x
5
in the expansion of
1
+
x
21
+
1
+
x
22
+
.
.
.
+
1
+
x
30
(a)
51
C
5
(b)
9
C
5
(c)
31
C
6
−
21
C
6
(d)
30
C
5
+
20
C
5
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Solution
(c)
31
C
6
−
21
C
6
We
have
1
+
x
21
+
1
+
x
22
+
.
.
.
1
+
x
30
=
1
+
x
21
1
+
x
10
-
1
1
+
x
-
1
=
1
x
1
+
x
31
-
1
+
x
21
Coefficient
of
x
5
in
the
given
expansion
=
Coefficient
of
x
5
in
1
x
1
+
x
31
-
1
+
x
21
=
Coefficient
of
x
6
in
1
+
x
31
-
1
+
x
21
=
31
C
6
-
21
C
6
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0
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