Question

The combined ages of a man and his son is 60 years. Twelve years ago, the father was five times as old as his son. Find their present ages.

Answer 1

Let the present age of son be x years,

Then, twelve years ago : $x-12$ = son's age

father's age = $5(x-12)$

The combined age $\Rightarrow 5(x-12)+(x-12)=60$

$\Rightarrow 5x-60+x-12=60$

$\Rightarrow x=22$ years

$\therefore$ The present age of son = $22$ years

father's age 12 yrs. age = $5(x-12)=50$ years

Father's present age $=50+12$

$=62$ years