The complex compound having maximum magnetic moment is:

{[{C o F}_{6}]}^{3 -}

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{[C r {({N H}_{3})}_{6}]}^{3 +}

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{[{F e F}_{6}]}^{3 -}

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{[M n {(C N)}_{6}]}^{4 -}

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Solution

The correct option is C ${[{F e F}_{6}]}^{3 -}$
In the given complexes the complex with maximum magnetic moment is $[F e F_{6}]^{3 -}$ because in this complex there are maximum numbered of unpaired electron, which is 5 and more the unpaired electrons more will be the magnetic movement. Therefore option C is correct.

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Similar questions

Q. The magnetic moments of complexes given below are in the order:

(I)

[N i (C O)_{4}]

(II)

[M n (C N)_{6}]^{4 -}

(III)

[C r (N H_{3})_{6}]^{3 +}

(IV)

[C o F_{6}]^{3 -}

Which of the following complexes are heteroleptic?
(a) $[C r (N H_{3})_{6}]^{3 +}$
(b) $[F e (N H_{3})_{4} C l_{2}]^{+}$
(c) $[M n (C N)_{6}]^{4 -}$
(d) $[C o (N H_{3})_{4} C l_{2}]$

Q. The increasing order of magnetic moment values of the given compounds is:

(I) [F e (C N)_{6}]^{4 -}

(I I) [F e (C N)_{6}]^{3 -}

(I I I) [C r (N H_{3})_{6}]^{3 +}

(I V) [N i (H_{2} O)_{6}]^{2 +}

Q. All the following complexes are found to be paramagnetic:

P : [F e F_{6}]^{3 -}; Q : [C o F_{6}]^{3 -}; R : [V (H_{2} O)_{6}]^{3 +}; S : [T i (H_{2} O)_{6}]^{3 +}

The correct order of their paramagnetic moment (spin only) is:

Q. What is the magnetic moment of

[F e F_{6}]^{3 -}

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The complex compound having maximum magnetic moment is:

The correct option is C [FeF6]3−In the given complexes the complex with maximum magnetic moment is [FeF6]3− because in this complex there are maximum numbered of unpaired electron, which is 5 and more the unpaired electrons more will be the magnetic movement. Therefore option C is correct.