The complex ion which has no $^{'} d^{'}$ electrons in the central metal atom is:

{[M n O_{4}]}^{-}

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{[C o {(N H_{3})}_{6}]}^{3 +}

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{[F e {(C N)}_{6}]}^{3 -}

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{[C r {(H_{2} O)}_{6}]}^{3 +}

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Solution

The correct option is A ${[M n O_{4}]}^{-}$
The complex ion which has no $^{'} d^{'}$ electrons in the central metal atom is ${[M n O_{4}]}^{-} .$ In ${[M n O_{4}]}^{-},$ the oxidation number of $M n$ is $+ 7$ i.e., all the $4 s$ and $3 d$ electrons are removed. It means $M n (V I I)$ .
So, $3 d^{0}$ , with no valence electrons.

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Similar questions

Q. Which complex ion has no

d

-electron in the central metal atom?

Q. The complex ion which has no d electrons in the central metal atom is: (At no.

C r = 24, M n = 25, F e = 26, C o = 27

)

Atomic number of Mn. Fe and Co are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamangetic?
(a) $[C o (N H_{3})_{6}]^{3 +}$
(b) $[M n (C N)_{6}]^{3 -}$
(c) $[F e (C N)_{6}]^{4 -}$
(d) $[F e (C N)_{6}]^{3 -}$

Q. For the complex ion

[F e (C N)_{6}]^{3 -}

, state:
(i) the type of hybridisation.
(ii) the magnetic behaviour.
(iii) the oxidation number of the central metal atom.

Q. Assertion :Complex ion

[C o (N H_{3})_{6}]^{2 +}

is readily oxidized to

[C o (N H_{3})_{6}]^{3 +}

Reason: Unpaired electron in complex ion

[C o (N H_{3})_{6}]^{2 +}

is present in 4p orbital.

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The complex ion which has no ′d′ electrons in the central metal atom is:

The correct option is A [MnO4]−The complex ion which has no ′d′ electrons in the central metal atom is [MnO4]−. In [MnO4]−, the oxidation number of Mn is +7 i.e., all the 4s and 3d electrons are removed. It means Mn(VII). So, 3d0, with no valence electrons.

The complex ion which has no $^{'} d^{'}$ electrons in the central metal atom is: