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Question

The complex number 1+2i1i lies in the :

A
1 quadrant
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B
II quadrant
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C
III quadrant
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D
IV quadrant
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Solution

The correct option is B II quadrant
H2i1i×1+i1+i=1+i+2i21+1
=12+3i2
x<0, y>0
IInd Quad (B)

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