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Question

The complex number z satisfying the equation |z|=z+1+2i is

A
322i
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B
32+2i
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C
232i
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D
32i2
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Solution

The correct option is A 322i
Let z=x+iy
Given that |z|=z+1+2i
x2+y2=x+iy+1+2i
x2+y2=(x+1)+(2+y)i
On comparing real and imaginary parts,
x2+y2=x+1
and 0=2+yy=2
x2+4=x+1
x2+4=x2+2x+1
2x=3
x=32
z=x+iy=322i

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