The complex number z satisfying the equation |z|=z+1+2i is
A
32−2i
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B
32+2i
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C
23−2i
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D
32−i2
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Solution
The correct option is A32−2i Let z=x+iy Given that |z|=z+1+2i ⇒√x2+y2=x+iy+1+2i ⇒√x2+y2=(x+1)+(2+y)i On comparing real and imaginary parts, √x2+y2=x+1 and 0=2+y⇒y=−2 ⇒√x2+4=x+1 ⇒x2+4=x2+2x+1 ⇒2x=3 ⇒x=32 ∴z=x+iy=32−2i