Question

The complex, $\left[Pt\right(Py\left)\right(N{H}_3\left)BrCl\right]$ will have how many geometrical isomers ?

• A. 3
• B. 4
• C. 2
• D. 0

Answer 1

The correct option is A 3

$\left[Pt\right(Py\left)\right(N{H}_3\left)\right(Br\left)\right(Cl\left)\right]$
$Pt$ favourably forms square planar complex.
In the given complex, all our ligands are different so the possible arrangements are
$\Rightarrow \left[M\right(abcd\left)\right]\to \left(ab\right)\left(cd\right)$
$\Rightarrow \left[M\right(abcd\left)\right]\to \left(ac\right)\left(bd\right)$
$\Rightarrow \left[M\right(abcd\left)\right]\to \left(ad\right)\left(bc\right)$

Thus, there are 3 possible geometrical isomerism.


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