The complex, $[P t (P y) (N H_{3}) B r C l]$ will have how many geometerical isomers?

2

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3

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4

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0

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Solution

The correct option is B $3$
The given complex is a type of [Mabcd] compound where the M is metal and a,b,c,d are 4 different ligands attached to it. This type of complexes forms 3 geometrical isomers as depicted in the image.

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