The correct option is
B 15.05%
In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.
However, here number of Fe2+ present = 0.93
Or No. of Fe2+ ions missing = 0.07
Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07×2 = 0.14
To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.
In short, 0.93 Fe2+ ions have 0.14 Fe3+ ions
100 Fe2+ ions have = 0.140.93×100 = 15.05%.