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Halogenation of Benzene

The compound ...

Question

The compound $C_{7} H_{8}$ undergoes the following reactions:

The product 'C' is:

3 - b r o m o - 2, 4, 6 - t r i c h l o r o t o l u e n e

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o - b r o m o t o l u e n e

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m - b r o m o t o l u e n e

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p - b r o m o t o l u e n e

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Solution

The correct option is C $m - b r o m o t o l u e n e$

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Similar questions

C_{7} H_{8}

C_{7} H_{8} - ----- \to 3 {C I}_{2} / Δ A - --- \to {B r}_{2} / F e B - ---- \to Z n / H C I C

^{'} C^{'}

Toluene, when treated with $B r_{2} / F e$ gives p-bromotoluene as the major product because the $C H_{3}$ group:

C_{7} H_{8}

C_{7} H_{8} 3 {C l}_{2} / Δ ⟶ A {B r}_{2} / F_{e} ⟶ B Z n / H c l ⟶ C

C

C_{7} H_{8}

C_{7} H_{8} 3 C l_{2} / △ - --- \to A B r_{2} / F e - --- \to B Z n / H C l - ---- \to C

C

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