Question

The compound in which all the bond angles around every atom are $109.28$ is:

• A. $HCOOH$
• B. ${\left({NH}_2\right)}_{2}CO$
• C. ${\left({CH}_3\right)}_{3}COH$
• D. ${\left({CH}_3\right)}_{3}CCHO$

Answer 1

Answer: (C)

${\left({CH}_3\right)}_{3}COH$

The bond angles around every atom will be ${109.28}^{\circ }$ for $s{p}^3$ hybridisation. This is followed by $(C{H}_3{)}_{3}COH$ only in the given options, as in this compound all carbon atoms are $s{p}^3$ hybridised with ${109.28}^{\circ }$.