The compound in which carbon uses only its $s p^{3}$ hybrid orbitals for bond formation is

HCOOH

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(NH₂)₂CO

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(CH₃)₃COH

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(CH₃)₃CHO

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Solution

The correct option is C
(CH₃)₃COH

All the carbon atoms are $s p^{3}$ hybridized.

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