The compound in which carbon uses $s p^{3}$ hybridisation for bond formation is:

H - C O O H

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(N H_{2})_{2} C = O

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H - C H O

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C H_{3} C H_{2} O H

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Solution

The correct option is C $C H_{3} C H_{2} O H$
The methyl group in ethanol has only single bonds and is thus $s p^{3}$ hybridized.

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The compound in which carbon uses only its $s p^{3}$ hybrid orbitals for bond formation is?

s p^{3}

C

s p^{3} - h y b r i d

s p^{3}

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