The compound which gives the most stable carbonium ion on dehydration is:

C H_{3} C H O H C H_{3}

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(C H_{3})_{3} C O H

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C H_{2} = C H - C H_{2} C H_{2} O H

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C H_{3} O H

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Solution

The correct option is B $(C H_{3})_{3} C O H$
The dehydration of tertiary alcohol proceeds via tertiary carbocation intermediate which is most stable.
$(C H_{3})_{3} C - O H tertiary alcohol_{+} H^{+} \to - H_{2} O (C H_{3})_{3} + C 3^{o} carbocation more stable$
$C H_{3} C H O H C H_{3}_{+} H^{+} \to - H_{2} O C H_{3} + C H - C H_{3} 2^{o} carbocation less stable$
$C H_{2} = C H - C H_{2} - C H_{2} O H_{+} H^{+} \to - H_{2} O C H_{2} = C H - {C H_{2} - C H_{2} 1^{o} carbocation (least stable)}^{+}$
Decreasing order of stability of carbocation is $t e r t i a r y > s e c o n d a r y > p r i m a r y > m e t h y l .$

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