The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

$\frac{3}{4}$

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$\frac{7}{3}$

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Solution

The correct option is B
$\frac{7}{3}$

$Y B a_{2} C u_{3} O_{7}$

$3 + 2 \times 2 + 3 x - (2 \times 7) = 0$

$3 + 4 + 3 x - 14 = 0$

$3 x = 7$

$x = \frac{7}{3}$

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Similar questions

The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

Q. In the compound

Y {B a}_{2} {C u}_{3} O_{7}

which shows superconductivity, what is the oxidation state of

C u

?
Assume that the rare earth element yttrium is in its usual +3 oxidation state.

Q. What is the oxidation state of copper in the compound,

Y B a_{2} C u_{3} O_{7}

which shows super conductivity? Assume that the rare earth element, yttrium is in its usual

+ 3

oxidation state.

Q. The compound

{Y b B a}_{2} {C u}_{3} O_{7}

, which shows superconductivity has copper in oxidation state

x

, then

x

is :
(Assume that the rare earth element ytterbium is in the usual

+ 3

oxidation state)

State whether the given statement is true or false:

The compound

Y {B a}_{2} {C u}_{3} O_{7}

which shows super conductivity has copper in oxidation state

+ \frac{7}{3}

. Assume that the rare earth element yttrium is in its usual

+ 3

oxidation state.

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The compound YBa2Cu3O7 which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

The correct option is B 73 YBa2Cu3O7 3+2×2+3x−(2×7)=0 3+4+3x−14=0 3x=7 x=73

The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

The correct option is B
$\frac{7}{3}$

$Y B a_{2} C u_{3} O_{7}$

$3 + 2 \times 2 + 3 x - (2 \times 7) = 0$

$3 + 4 + 3 x - 14 = 0$

$3 x = 7$

$x = \frac{7}{3}$