The compressibility of water 5×1010m2N−1 The decrease in volume of 100ml of water when subjected to a pressure of 15MPa:
Given,
Compressibility, k=5×10−10m2N−1
Volume is V=100mL
Change in pressure ΔP=15×106−0=15×106Pa
Compressibility k=−ΔVVΔP
Decrease in volume,
−ΔV=kVΔP=5×10−10×100×15×106
−ΔV=0.75mL
Hence, change in volume is 0.75mL