Question

The concentration of a reactant changes from $0.06M$ to $0.04M$ in $20secs$. What is the average rate of the reaction?

• A. $0.001$
• B. $0.002$
• C. $0.003$
• D. $0.004$

Answer 1

The correct option is A $0.001$

The concentration changes from $0.06M$ to $0.04M$, that is $x_2$ is $0.04$ and $x_1$ is $0.06$. The average rate is given by $-$$\frac{x_2-x_1}{t_2-t_1}$. The time interval is $20$.

Thus the value of average velocity is $0.001mol.L^{-1}se{c}^{-1}$