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Question

The concentration of cation vacancies in NaCl crystal doped with CdCl2 is found to be 6.02×1016 mol1. What is the concentration of CdCl2 added to it?

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Solution

No.ofcationvacancies=6.02×1016mol1NaCl=107×6.02×1023mol1NaCl=107mole/moleofNaClHenceonemoleofNaClisdopedwith107moleofCdCl2

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