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Methods to Form Lyophobic Colloids

the conductiv...

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the conductivities at infinite dilution of NH_4Cl,NaOHand NaCl are 130,218,120 ohm^{-1}cm^2eq^{-1}.If equivalent conduc†an ce ofN/100 solution of NH_4OH is 10,the degree of dissociation of

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Q. The conductivities at infinite dilution of

N H_{4} C l, N a O H

N a C l

130, 218, 120

o h m^{- 1}

c m^{2}

e q^{- 1}

. If equivalent conductance of

\frac{N}{100}

N H_{4} O H

10

o h m^{- 1}

c m^{2}

e q^{- 1}

, then degree of dissociation of

N H_{4} O H

at this dilution is:

Q. The conductivity at infinite dilution of

{N H}_{4} C l, N a O H

N a C l

130, 218,

120 {o h m}^{- 1} {c m}^{2} {e q}^{- 1}

. If equivalent conductance of

\frac{N}{100}

{N H}_{4} O H

10

, then degree of dissociation of

{N H}_{4} O H

at this dilution is:

18^{\circ} C

, the conductivities at infinite dilution of

N H_{4} C l, N a O H

N a C l

129.8, 217.4

108.9

mho respectively. If the equivalent conductivity of

N / 100

N H_{4} O H

9.93 m h o

, calculate the degree of dissociation of

N H_{4} O H

at this dilution.

Equivalent conductance at infinite dilution, $λ^{0}$ of NH $_{4}$ Cl, NaOH and NaCl are 128.0, 217.8 and 109.9 $o h m^{- 1} c m^{2} e q^{- 1}$ respectively. The equivalent conductance of 0.01 N $N H_{4} O H$ is 9.30 $o h m^{- 1} c m^{2} e q^{- 1}$ , then the degree of ionization of $N H_{4} O H$ at this temperature would be:

Equivalent conductance of 1 M propanoic acid is 10 $o h m^{- 1} c m^{2} e q^{- 1}$ and that at infinite dilution 200 $o h m^{- 1} c m^{2} e q^{- 1}$ . The pH of the propanoic acid solution is:

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