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Question

The conductivity of 0.01 mol/dm3 aqueous acetic acid at 300 K is 19.5×105ohm1cm1 and the limiting molar conductivity of acetic acid at the same temperature is 390 ohm1cm2mol1. The degree of dissociation of acetic acid is:

A
0.5
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B
0.05
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C
5×103
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D
5×107
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Solution

The correct option is B 0.05
Data:-
Concentration(C)=0.01moldm3=10molm3.
Conductivity(K)=19.5×105Scm1=19.5×103Sm1
Limiting molar conductivity(m)=390Scm2mol1=390×104Sm2mol1
Solution:-
(i) Molar Conductivitym=KC=19.5×103Sm110molm3
m=19.5×104Sm2mol1.
(ii) Degree of dissociation(α)=mm=19.5×104Sm2mol1390×104Sm2mol1
α=0.05


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