Question

The conductivity of 0.2 M KCl solution is $3\times {10}^{-2}oh{m}^{-1}c{m}^{-1}$. Calculate its molar conductance.

Answer 1

Given : Conductivity $=3\times {10}^{-2}oh{m}^{-1}c{m}^{-1}$
Molarity $=0.2M$
Now, ${\Lambda }_{molar}=\frac{1000\times conductivity}{Molarity}$
$=\frac{1000\times 3\times {10}^{-2}}{0.2}=150ohmc{m}^{2}mo{l}^{-1}$