Question

The conductivity of 0.20 M solution of $KCl$ at 298 K is $0.0248Sc{m}^{-1}$. Calculate its molar conductivity.

• A. $112Sc{m}^{2}mo{l}^{-1}$
• B. $124Sc{m}^{2}mo{l}^{-1}$
• C. $136Sc{m}^{2}mo{l}^{-1}$
• D. $148Sc{m}^{2}mo{l}^{-1}$

Answer 1

The correct option is B $124Sc{m}^{2}mo{l}^{-1}$

$k$ (Conductivity) $=0.0248Sc{m}^{-1}$

$C$ (molarity) $=0.20M$

$T$ (temperature) $=298K$

${\Lambda }_m=?$ (molar conductivity)

The formula is ${\Lambda }_m=\frac{1000\times k}{C}$

$=\frac{1000\times 0.0248Sc{m}^{-1}}{0.20molc{m}^{-3}}$

$=124Sc{m}^{2}mo{l}^{-1}$

The molar conductivity is $124Sc{m}^{2}mo{l}^{-1}$