Question

# The conductivity of $$0.20\ M$$ solution of $$KCl$$ at $$298\ K$$ is $$0.025\ S\ cm^{-1}$$. Calculate its molar conductivity.

Solution

## Given, $$K=0.025 S cm^{-1} and C=0.2 M$$Formula of molar conductivity,$$\Lambda_m=\dfrac{\kappa_m\times 1000}C$$=$$\dfrac{0.025\times 1000}{0.2}$$=$$125\ S cm^2mol^{-1}$$Chemistry

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