Question

The conductivity of 0.20M solution of KCl at 298K is 0.0248 S $c{m}^{-1}$. Calculate its molar conductivity ?

Answer 1

Conductivity $\left(k\right)=0.0248Sc{m}^{-1}=0.0248oh{m}^{-1}c{m}^{-1}$

Molar concentration (C) $0.20mol{L}^{-1}$

$=\frac{\left(0.2mol\right)}{\left(1000c{m}^3\right)}=2.0\times {10}^{-4}molc{m}^{-3}$

Molar conductivity $\left({\lambda }_m\right)=\frac{k}{C}=\frac{\left(0.0248oh{m}^{-1}\right)c{m}^{-1}}{(2.0\times {10}^{-4}molc{m}^{-3})}$

$=124oh{m}^{-1}mo{l}^{-1}c{m}^2$

$or124Smo{l}^{-1}c{m}^2$

Molar conductivity $124Smo{l}^{-1}c{m}^2$