Question

The configuration of $1s^2,2s^2,2p^6,3s^2,3p^2$ shows ?

• A. $Si$
• B. Excited state of neon
• C. Excited state of fluorine
• D. Ground state of fluorine atom

Answer 1

The correct option is A $Si$

solution:

The superscripts (2, 2, 6, 2 and 2) are the number of electrons in each orbital. Simply add up these numbers, which will give you 14.

Now just look for the element on the periodic table with the atomic number of 14.

This is because the atomic number tells you the number of protons, and the number of electrons is equal to that of the protons

So, the element with the atomic number of 14 is Silicon

options B and C are false as neon and F have to gain 4 and 5 electrons respectively to reach this state it should and that will not be stable and this doesn't their state too $N{e}^{4+}and{F}^{5+}X$

hence the correct option: A