Question

The connection of two 2-port networks is shown in the figure. The ABCD parameters of $N_1$ and $N_2$ networks are given as

${\left[\begin{array}{cc}A& B\\ C& D\end{array}\right]}_{N1}$ = $\left[\begin{array}{cc}1& 5\\ 0& 1\end{array}\right]$

and

${\left[\begin{array}{cc}A& B\\ C& D\end{array}\right]}_{N2}$ = $\left[\begin{array}{cc}1& 0\\ 0.2& 1\end{array}\right]$



The ABCD parameters of the combined 2-port network are

• A. $\left[\begin{array}{cc}2& 5\\ 0.2& 1\end{array}\right]$
• B. $\left[\begin{array}{cc}1& 2\\ 0.5& 1\end{array}\right]$
• C. $\left[\begin{array}{cc}5& 2\\ 0.5& 1\end{array}\right]$
• D. $\left[\begin{array}{cc}1& 2\\ 0.5& 5\end{array}\right]$

Answer 1

The correct option is A $\left[\begin{array}{cc}2& 5\\ 0.2& 1\end{array}\right]$

$\left[\begin{array}{cc}A& B\\ C& D\end{array}\right]=\left[\begin{array}{cc}1& 5\\ 0& 1\end{array}\right]\left[\begin{array}{cc}1& 0\\ 0.2& 1\end{array}\right]$

$\left[\begin{array}{cc}A& B\\ C& D\end{array}\right]=\left[\begin{array}{cc}2& 5\\ 0.2& 1\end{array}\right]$